JEE Main & Advanced Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति Question Bank Power

  • question_answer
    A car of mass 1250 kg is moving at 30m/s. Its engine delivers 30 kW while resistive force due to surface is 750N. What max acceleration can be given in the car           [RPET 2000]

    A)             \[\frac{1}{3}\,m/{{s}^{2}}\]

    B)               \[\frac{1}{4}m/{{s}^{2}}\]

    C)             \[\frac{1}{5}\,m/{{s}^{2}}\]

    D)               \[\frac{1}{6}\,m/{{s}^{2}}\]

    Correct Answer: C

    Solution :

                Force produced by the engine\[F=\frac{P}{v}\,=\,\frac{30\times {{10}^{3}}}{30}\]=103N Acceleration=\[\frac{\text{Forward force by engine--resistive force}}{\text{mass of car}}\] \[=\frac{1000-750}{1250}=\frac{250}{1250}\]=\[\frac{1}{5}m/{{s}^{2}}\]


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