A) \[1.025MW\]
B) \[2.05MW\]
C) \[5MW\]
D) \[6MW\]
Correct Answer: B
Solution :
Power\[=\frac{\text{Work done}}{\text{time}}=\frac{\frac{1}{2}m({{v}^{2}}-{{u}^{2}})}{t}\] P\[=\frac{1}{2}\times \frac{2.05\times {{10}^{6}}\times [{{(25)}^{2}}-({{5}^{2}})]}{5\times 60}\] \[P=2.05\times {{10}^{6}}\,W=2.05\,MW\]
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