A) 2000 W
B) 22500 W
C) 5000 W
D) 2250 W
Correct Answer: B
Solution :
Power\[=\frac{\text{Work done}}{\text{time}}=\frac{\text{Increase in K}\text{.E}\text{.}}{\text{time}}\] \[P=\frac{\frac{1}{2}m{{v}^{2}}}{t}=\frac{\frac{1}{2}\times {{10}^{3}}\times {{(15)}^{2}}}{5}=22500\,W\]
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