A) \[3.3kW\]
B) \[0.33kW\]
C) \[0.033kW\]
D) \[33kW\]
Correct Answer: A
Solution :
Work output of engine = mgh = \[100\times 10\times 10={{10}^{4}}J\] Efficiency (h) = \[\frac{\text{output}}{\text{input}}\] \ Input energy = \[\frac{\text{outupt}}{\eta }\] \[=\frac{{{10}^{4}}}{60}\times 100=\frac{{{10}^{5}}}{6}J\] \ Power = \[\frac{\text{input energy}}{\text{time}}\]= \[\frac{{{10}^{5}}/6}{5}=\frac{{{10}^{5}}}{30}=3.3\ kW\]
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