JEE Main & Advanced Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति Question Bank Power

  • question_answer
    A force of \[2\hat{i}+3\hat{j}+4\hat{k}\ N\]acts on a body for 4 second, produces a displacement of \[(3\hat{i}+4\hat{j}+5\hat{k})m.\]The power used is          [Pb. PET 2001; CBSE PMT 2001]

    A)             9.5 W  

    B)             7.5 W

    C)             6.5 W  

    D)             4.5 W

    Correct Answer: A

    Solution :

    \[P=\frac{\overrightarrow{F}.\overrightarrow{s}}{t}=\frac{(2\hat{i}+3\hat{j}+4\hat{k}).(3\hat{i}+4\hat{j}+5\hat{k})}{4}\]\[=\frac{38}{4}=9.5\ W\]


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