A) DE is the hypotenuse of \[\Delta DEF\].
B) \[\angle E+\angle D={{90}^{o}}\]
C) \[EF=3cm\]
D) All the above.
Correct Answer: D
Solution :
By Pythagoras' theorem, one of the perpendicular sides is 3 cm. and by angle sum property, \[\angle D+\angle E={{180}^{o}}-\angle F\]\[={{180}^{o}}-{{90}^{o}}={{90}^{o}}\]You need to login to perform this action.
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