JEE Main & Advanced Chemistry Carboxylic Acids Question Bank Preparation of Carboxylic Acids and Their Derivatives

  • question_answer
    Hydrolysis of \[C{{H}_{3}}C{{H}_{2}}N{{O}_{2}}\] with 85% \[{{H}_{2}}S{{O}_{4}}\] gives [KCET 1996]

    A)                 \[C{{H}_{3}}C{{H}_{2}}OH\]        

    B)                 \[{{C}_{2}}{{H}_{6}}\]

    C)                 \[C{{H}_{3}}CH=NOH\] 

    D)                 \[C{{H}_{3}}COOH\]

    Correct Answer: D

    Solution :

               \[C{{H}_{3}}C{{H}_{2}}N{{O}_{2}}+{{H}_{2}}O\xrightarrow{{{H}_{2}}S{{O}_{4}}}\]\[C{{H}_{3}}COOH+N{{H}_{2}}OH\]


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