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JEE Main & Advanced Chemistry Carboxylic Acids Question Bank Preparation of Carboxylic Acids and Their Derivatives

  • question_answer
    Two moles of acetic acid are heated with \[{{P}_{2}}{{O}_{5}}.\] The product formed is                                  [MP PET/PMT 1988]

    A)                 2 moles of ethyl alcohol               

    B)                 Formic anhydride

    C)                 Acetic anhydride

    D)                 2 moles of methyl cyanide

    Correct Answer: C

    Solution :

                    \[\begin{matrix}    C{{H}_{3}}COOH  \\    C{{H}_{3}}COOH  \\ \end{matrix}+{{P}_{2}}{{O}_{5}}\to \begin{matrix}    C{{H}_{3}}-CO  \\    C{{H}_{3}}-CO  \\ \end{matrix}\,>O+{{H}_{2}}O\]


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