A) \[{{P}_{2}}{{O}_{5}}\]
B) \[{{H}_{2}}S{{O}_{4}}\]
C) \[C{{H}_{3}}COONa\]
D) \[C{{H}_{3}}COOH\]
Correct Answer: C
Solution :
\[C{{H}_{3}}-COO\underline{Na}+C{{H}_{3}}-CO-\underline{Cl}\to \underset{\text{Acetic anhydride}}{\mathop{C{{H}_{3}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-O-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-C{{H}_{3}}}}\,+NaCl\]
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