A) Acetamide
B) Formamide
C) Ammonium cyanate
D) Urea
Correct Answer: A
Solution :
\[\underset{\text{Ammonium acetate}}{\mathop{C{{H}_{3}}COON{{H}_{4}}}}\,+C{{H}_{3}}COOH\xrightarrow{{{110}^{o}}C}\] \[\underset{\text{Acetamide}}{\mathop{C{{H}_{3}}CON{{H}_{2}}}}\,+{{H}_{2}}O\]You need to login to perform this action.
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