A) \[C{{H}_{3}}CON{{H}_{2}}\xrightarrow{KOH.B{{r}_{2}}}\]
B) \[C{{H}_{3}}CN\xrightarrow{LiAl{{H}_{4}}}\]
C) \[C{{H}_{3}}NC\xrightarrow{LiAl{{H}_{4}}}\]
D) \[C{{H}_{3}}CON{{H}_{2}}\xrightarrow{LiAl{{H}_{4}}}\]
Correct Answer: C
Solution :
\[C{{H}_{3}}-N\equiv C\xrightarrow{LiAl{{H}_{4}}}\underset{\text{sec}\text{.}\,\,\text{amine}}{\mathop{C{{H}_{3}}-NH-C{{H}_{3}}}}\,\]
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