A) \[{{C}_{6}}{{H}_{5}}-N=N-{{C}_{6}}{{H}_{5}}\,,\,{{C}_{6}}{{H}_{5}}N_{2}^{\oplus }C{{l}^{\Theta }}\]
B) \[{{C}_{6}}{{H}_{5}}N_{2}^{\oplus }C{{l}^{\Theta }},\,{{C}_{6}}{{H}_{5}}-N=N-{{C}_{6}}{{H}_{5}}\]
C) \[{{C}_{6}}{{H}_{5}}N_{2}^{\oplus }C{{l}^{\Theta }},\,{{C}_{6}}{{H}_{5}}N{{O}_{2}}\]
D) \[{{C}_{6}}{{H}_{5}}N{{O}_{2}},\,{{C}_{6}}{{H}_{6}}\]
Correct Answer: C
Solution :
\[{{C}_{6}}{{H}_{5}}N{{H}_{2}}\underset{{{0}^{o}}C-{{5}^{o}}C}{\mathop{\xrightarrow{NaN{{O}_{2}}/HCl}}}\,\underset{\text{(X)}}{\mathop{{{C}_{6}}{{H}_{5}}N_{2}^{+}C{{l}^{-}}}}\,\underset{{{H}_{2}}O}{\mathop{\xrightarrow{HN{{O}_{2}}}}}\,\]\[\underset{\text{(Y)}}{\mathop{{{C}_{6}}{{H}_{5}}N{{O}_{2}}}}\,+{{N}_{2}}+HCl\]You need to login to perform this action.
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