A) \[C{{H}_{3}}-CH=CH-C{{H}_{3}}\]
B) \[{{(C{{H}_{3}})}_{2}}C=C{{(C{{H}_{3}})}_{2}}\]
C) \[{{C}_{6}}{{H}_{5}}CH=C{{H}_{2}}\]
D) \[C{{H}_{3}}CH=C{{H}_{2}}\]
Correct Answer: B
Solution :
\[{{(C{{H}_{3}})}_{2}}C=C{{(C{{H}_{3}})}_{2}}\xrightarrow{{{O}_{3}}}2C{{H}_{3}}-CO-C{{H}_{3}}\]
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