JEE Main & Advanced Physics Fluid Mechanics, Surface Tension & Viscosity / द्रव यांत्रिकी, भूतल तनाव और चिपचिपापन Question Bank Pressure Difference

  • question_answer
    A capillary tube of radius r is dipped in a liquid of density r and surface tension S. If the angle of contact is q, the pressure difference between the two surfaces in the beaker and the capillary

    A)             \[\frac{S}{r}\cos \theta \]

    B)                      \[\frac{2S}{r}\cos \theta \]

    C)             \[\frac{S}{r\cos \theta }\]       

    D)             \[\frac{2S}{r\cos \theta }\]

    Correct Answer: B

    Solution :

                    \[S=\frac{rhdg}{2\cos \theta }\Rightarrow \]Pressure difference \[=hdg=\frac{2S}{r}\cos \theta \]


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