JEE Main & Advanced Physics Fluid Mechanics, Surface Tension & Viscosity / द्रव यांत्रिकी, भूतल तनाव और चिपचिपापन Question Bank Pressure Difference

  • question_answer
    The radii of two soap bubbles are r1 and r2. In isothermal conditions, two meet together in vaccum. Then the radius of the resultant bubble is given by [MP PMT 2001; RPET 1999; EAMCET 2003]

    A)             \[R=({{r}_{1}}+{{r}_{2}})/2\]

    B)                      \[R={{r}_{1}}({{r}_{1}}{{r}_{2}}+{{r}_{2}})\]

    C)             \[{{R}^{2}}=r_{1}^{2}+r_{2}^{2}\]

    D)                      \[R={{r}_{1}}+{{r}_{2}}\]

    Correct Answer: C

    Solution :

       


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