A) H
B) 2H
C) 7H
D) 8H
Correct Answer: C
Solution :
\[{{P}_{1}}{{V}_{1}}={{P}_{2}}{{V}_{2}}\] Þ\[(H+h)\rho g\times \frac{4}{3}\pi {{r}^{3}}\]\[=H\times \frac{4}{3}\pi {{(2r)}^{3}}\] \[\Rightarrow H+h=8H\]\ \[h=7H\]
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