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JEE Main & Advanced Physics Fluid Mechanics, Surface Tension & Viscosity / द्रव यांत्रिकी, भूतल तनाव और चिपचिपापन Question Bank Pressure Difference

  • question_answer
    A soap bubble in vacuum has a radius of 3 cm and another soap bubble in vacuum has a radius of 4 cm. If the two bubbles coalesce under isothermal condition, then the radius of the new bubble is              [MP PMT/PET 1998; JIPMER 2000]

    A) 2.3 cm

    B)                      4.5 cm

    C)             5 cm   

    D)  7 cm

    Correct Answer: C

    Solution :

                    \[r=\sqrt{r_{1}^{2}+r_{2}^{2}}=\sqrt{9+16}=5\ cm\]


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