A) 10m
B) 20m
C) 60m
D) 30m
Correct Answer: B
Solution :
Pressure at half the depth \[={{P}_{0}}+\frac{h}{2}dg\] Pressure at the bottom \[={{P}_{0}}+h\rho g\] According to given condition \[{{P}_{0}}+\frac{h}{2}dg=\frac{2}{3}({{P}_{0}}+hdg)\] Þ\[3{{P}_{0}}+\frac{3h}{2}dg=2{{P}_{0}}+2hdg\] \[\Rightarrow h=\frac{2{{P}_{0}}}{dg}=\frac{2\times {{10}^{5}}}{{{10}^{3}}\times 10}=20\ m\]
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