A) 1 : 4
B) 4 : 1
C) 16 : 1
D) 1 : 16
Correct Answer: A
Solution :
\[\Delta P\propto \frac{1}{r}\Rightarrow \frac{\Delta {{P}_{1}}}{\Delta {{P}_{2}}}=\frac{{{r}_{2}}}{{{r}_{1}}}=\frac{r}{4r}=\frac{1}{4}\]
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