A) \[2.054\times {{10}^{3}}Pa\]
B) \[1.027\times {{10}^{3}}Pa\]
C) \[1.027\times {{10}^{5}}Pa\]
D) \[2.054\times {{10}^{5}}Pa\]
Correct Answer: C
Solution :
Excess pressure inside the air bubble \[=\frac{2T}{r}\] \[\Rightarrow {{P}_{in}}-{{P}_{out}}=\frac{2T}{r}=\frac{2\times 70\times {{10}^{-3}}}{0.1\times {{10}^{-3}}}=1400Pa\] Þ \[{{P}_{in}}=1400+1.013\times {{10}^{5}}\]\[=0.014\times {{10}^{5}}+1.013\times {{10}^{5}}=1.027\times {{10}^{5}}Pa\]
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