A) 10 Pa
B) 20 Pa
C) 5 Pa
D) None of the above
Correct Answer: B
Solution :
Excess pressure \[\Delta P=\frac{4T}{r}\] \[=\frac{4\times 2\times 25\times {{10}^{-3}}}{1\times {{10}^{-2}}}\]\[=20\ N/{{m}^{2}}=20\ Pa\]\[\left[ \text{as }r=\frac{d}{2} \right]\]
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