A) 2.6°
B) 3°
C) 4°
D) 5.33°
Correct Answer: B
Solution :
For dispersion without deviation \[\frac{A}{{{A}'}}\]= \[\frac{({\mu }'-1)}{(\mu -1)}\] \[\frac{4}{{{A}_{F}}}=\frac{(1.72-1)}{(1.54-1)}=\frac{0.72}{0.54}\] or \[{{A}_{F}}=\frac{4\times 0.54}{0.72}={{3}^{o}}\]You need to login to perform this action.
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