JEE Main & Advanced Physics Question Bank Prism Theory and Dispersion of Light

  • question_answer
    A prism of refracting angle 60o is made with a material of refractive index m.  For a certain wavelength of light, the angle of minimum deviation is 30o. For this, wavelength the value of refractive index of the material is [CPMT 1999, MH CET 2000]

    A)            1.231                                       

    B)            1.820

    C)            1.503                                       

    D)            1.414

    Correct Answer: D

    Solution :

               \[\mu =\frac{\sin \,\left( \frac{A+{{\delta }_{m}}}{2} \right)}{\sin \,\left( \frac{A}{2} \right)}\]\[=\frac{\sin \left( \frac{60{}^\circ +30{}^\circ }{2} \right)}{\sin \frac{60{}^\circ }{2}}\]=\[\frac{\sin {{45}^{o}}}{\sin {{30}^{o}}}\]=1.414


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