A) 42o
B) 45 o
C) 50 o
D) 52 o
Correct Answer: B
Solution :
\[A={{60}^{o}},\,{{\delta }_{m}}={{30}^{o}}\]so \[\mu =\frac{\sin \left( \frac{A+{{\delta }_{m}}}{2} \right)}{\sin \left( \frac{A}{2} \right)}\] \[\mu =\frac{\sin \left( \frac{60{}^\circ +30{}^\circ }{2} \right)}{\sin \left( \frac{60{}^\circ }{2} \right)}=\frac{\sin 45{}^\circ }{\sin 30{}^\circ }=\sqrt{2}\] Also \[\mu =\frac{1}{\sin C}\Rightarrow C={{\sin }^{-1}}\left( \frac{1}{\mu } \right)\Rightarrow C={{45}^{o}}\]
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