A) \[\sqrt{\omega d}\,+\,\sqrt{{\omega }'{d}'}=0\]
B) \[{\omega }'d+\omega {d}'=0\]
C) \[\omega d+{\omega }'{d}'=0\]
D) \[{{(\omega d)}^{2}}+{{({\omega }'{d}')}^{2}}=0\]
Correct Answer: C
Solution :
\[{{\theta }_{net}}=\theta +{\theta }'=0\]\[\Rightarrow \omega d+{\omega }'{d}'=0\] (\[\theta \]= Angular dispersion =\[\omega .\ {{\delta }_{y}}\])
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