A) 1/8
B) 1/2
C) 3/4
D) 1/4
Correct Answer: D
Solution :
\[\frac{{{\delta }_{w}}}{{{\delta }_{a}}}=\frac{{{(}_{w}}{{\mu }_{g}}-1)}{{{(}_{a}}{{\mu }_{g}}-1)}\]\[=\frac{\left( \frac{9}{8}-1 \right)}{\left( \frac{3}{2}-1 \right)}=\frac{1}{4}\]You need to login to perform this action.
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