A) 5° 24?
B) 4° 30?
C) 6°
D) 8°
Correct Answer: B
Solution :
\[\frac{{{A}'}}{A}=\frac{({{\mu }_{y}}-1)}{({{\mu }_{y'}}-1)}\Rightarrow \frac{{{A}'}}{6}=-\frac{(1.54-1)}{(1.72-1)}\] Þ A' \[=-\,{{4.5}^{o}}={{4}^{o}}3{0}'\]You need to login to perform this action.
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