A) 18° 36?
B) 20° 30?
C) 18°
D) 22°1?
Correct Answer: A
Solution :
For surface \[AC\frac{1}{\mu }=\frac{\sin 30{}^\circ }{\sin e}\Rightarrow \sin e=\mu \sin 30{}^\circ \] \[\Rightarrow \] \[\sin e=1.5\times \frac{1}{2}=0.75\] \[\Rightarrow \] e = \[{{\sin }^{-1}}(0.75)={{48}^{o}}3{6}'\] From figure \[\delta =e-{{30}^{o}}\] \[={{48}^{o}}\,3{6}'-{{30}^{o}}\]=\[{{18}^{o}}3{6}'\]You need to login to perform this action.
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