A) 26o
B) 0 o
C) 23 o
D) 15 o
Correct Answer: D
Solution :
\[A={{30}^{o}},\mu =\sqrt{2}\]. As we know \[A={{r}_{1}}+{{r}_{2}}\]=\[0+{{r}_{2}}\Rightarrow A={{r}_{2}}\]. Applying Snell?s law for the surface \[AC\] \[\frac{1}{\mu }\]= \[\frac{\sin {{r}_{2}}}{\sin e}=\frac{\sin A}{\sin e}\] \[\Rightarrow \]\[\frac{1}{\sqrt{2}}=\frac{\sin {{30}^{o}}}{\sin e}\Rightarrow e={{45}^{o}}\] \[\delta =e-{{r}_{2}}={{45}^{o}}-{{30}^{o}}=15{}^\circ \]You need to login to perform this action.
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