A) \[\frac{1}{10}\]
B) \[\frac{9}{100}\]
C) \[\frac{1}{100}\]
D) \[\frac{2}{100}\]
Correct Answer: A
Solution :
\[\text{E }=\{\text{1},\text{4},\text{9},\text{16},\text{25},\text{36},\text{49},\text{64},\text{81},\text{1}00\}\] \[\text{n(E)=1}0\] \[\text{S}=\{\text{1},\text{ 2},\text{ 3},\text{ }......\text{ 1}00\}\text{ }\Rightarrow \text{ n(S)}=\text{1}00\] \[\therefore \]\[p(E)=\frac{n(E)}{n(S)}=\frac{10}{100}=\frac{1}{10}\]
You need to login to perform this action.
You will be redirected in
3 sec
