A) \[\frac{1}{3}\]
B) \[\frac{1}{4}\]
C) \[\frac{1}{2}\]
D) \[\frac{1}{6}\]
Correct Answer: C
Solution :
(c): No. of patches have three shared fences \[=8=n(E)\] Total patches \[=16=n\left( S \right)\] \[n(P)=\frac{n\left( E \right)}{n(S)}=\frac{8}{16}=~\frac{1}{2}\]You need to login to perform this action.
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