A) \[\frac{1}{6}\]
B) \[\frac{1}{36}\]
C) \[\frac{1}{2}\]
D) \[\frac{1}{12}\]
Correct Answer: C
Solution :
\[E=\{2,4,6\}\Rightarrow n(E)=3\] \[S=\{1,2,3,4,5,6\}\Rightarrow n(S)=6\] \[\therefore \] \[p(E)=\frac{n(E)}{n(S)}=\frac{3}{6}=\frac{1}{2}\]
You need to login to perform this action.
You will be redirected in
3 sec
