question_answer

The probability that a student will pass in mathematics is 3/5 and the probability that he will pass in English is 1/3. If the probability that he will pass in both mathematics and English is 1/8, what is the probability that he will pass in at least one subject?

A)  \[\frac{97}{120}\]                    

B)  \[\frac{87}{120}\]

C)  \[\frac{53}{120}\]                                

D)  \[\frac{120}{297}\]

Correct Answer: A

Solution :

(a): \[P(pass)=P(A\cup B)\] \[=\frac{18}{40}+\frac{1}{8}+\frac{5}{24}\] We have: \[19/40+1/8+5/24-97/120\]