A) \[\frac{97}{120}\]
B) \[\frac{87}{120}\]
C) \[\frac{53}{120}\]
D) \[\frac{120}{297}\]
Correct Answer: A
Solution :
(a): \[P(pass)=P(A\cup B)\] \[=\frac{18}{40}+\frac{1}{8}+\frac{5}{24}\] We have: \[19/40+1/8+5/24-97/120\]You need to login to perform this action.
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