(i) gives more than 20p? |
(ii) has less than Rs. 5 left in her pocket? |
A)
(i) (ii) 1 \[\frac{1}{2}\]
B)
(i) (ii) \[\frac{1}{2}\] 1
C)
(i) (ii) \[\frac{3}{4}\] \[\frac{1}{2}\]
D)
(i) (ii) \[\frac{1}{2}\] \[\frac{3}{4}\]
Correct Answer: A
Solution :
Total number of coins = 4. (i) Since Tanya has coins of Rs. 1, Rs. 2, 5 and Rs. 10 all of which are more than 20 p. Total number of possible outcomes = 4 Required probability (ii) Coins less than Rs. 5 are Rs. 1 and Rs. 2 which are 2 in number. Favourable outcomes = 2 Required probabilityYou need to login to perform this action.
You will be redirected in
3 sec