question_answer

Tanya has the following coins in her pocket: Rs. 1, Rs. 2, Rs. 5, Rs. 10. She selects one coin at random to put in a charity collection box. What is the probability that she

(i) gives more than 20p?

(ii) has less than Rs. 5 left in her pocket?

A)

(i)	(ii)
1	\[\frac{1}{2}\]

           

B)

(i)	(ii)
\[\frac{1}{2}\]	1

           

C)

(i)	(ii)
\[\frac{3}{4}\]	\[\frac{1}{2}\]

           

D)

(i)	(ii)
\[\frac{1}{2}\]	\[\frac{3}{4}\]

Correct Answer: A

Solution :

        Total number of coins = 4. (i) Since Tanya has coins of Rs. 1, Rs. 2, 5 and Rs. 10 all of which are more than 20 p. Total number of possible outcomes = 4  Required probability (ii) Coins less than Rs. 5 are Rs. 1 and Rs. 2 which are 2 in number. Favourable outcomes = 2 Required probability