Number of head in a trial | 0 | 1 | 2 |
Frequency | 20 | 35 | 25 |
A) \[\frac{3}{4}\]
B) \[\frac{5}{16}\]
C) \[\frac{1}{2}\]
D) \[\frac{2}{9}\]
Correct Answer: A
Solution :
From the data given the probability of getting atleast one head \[=\frac{35+25}{80}\] \[=\frac{60}{80}=\frac{3}{4}\] (\[\because \]Atleast one head means one or more htan on head.)You need to login to perform this action.
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