A) 0.75
B) 0.25
C) - 0.25
D) 0.5
Correct Answer: A
Solution :
Total no. of balls = 32 No. of sixer hits = 8 \[\therefore \]Probability that a sixer is not hit in a ball \[=\frac{32-8}{32}=\frac{24}{32}=0.75\]You need to login to perform this action.
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