A) \[\frac{9}{25}\]
B) \[\frac{16}{25}\]
C) \[\frac{11}{25}\]
D) \[\frac{6}{25}\]
Correct Answer: B
Solution :
\[S=\{1,2,3,4,........,25\}\] Let E= event of getting a prime number \[=\{2,3,5,7,11,13,17,19,23\}.\] Then, \[n(E)=9.\] \[\therefore \]\[P(E)=\frac{n(E)}{n(S)}=\frac{9}{25}\] Required probability \[=1-P(E)\] \[=\left( 1-\frac{9}{25} \right)=\frac{16}{25}\]You need to login to perform this action.
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