Outcomes | 1 | 2 | 3 | 4 | 5 | 6 |
Frequency | 22 | 13 | 20 | 10 | 25 | 10 |
A) \[\frac{11}{50}\]
B) \[\frac{1}{5}\]
C) \[\frac{67}{100}\]
D) \[\frac{1}{4}\]
Correct Answer: C
Solution :
In 100 trials, total number of odd numbers is 22 + 20 + 25 = 67 \[P(an\,odd\,no.)=\frac{67}{100}\]You need to login to perform this action.
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