A) \[7x-9y+4=0\]
B) \[9x-7y-4=0\]
C) \[9x+7y+4=0\]
D) \[7+9y+4=0\]
Correct Answer: C
Solution :
According to question , \[{{x}_{1}}=\frac{2+4+x}{3}\Rightarrow x=3{{x}_{1}}-6\] \[{{y}_{1}}=\frac{5-11+y}{3}\Rightarrow y=3{{y}_{1}}+6\] \[\therefore \] \[9(3{{x}_{1}}-6)+7(3{{y}_{1}}+6)+4=0\] Hence locus is\[27x+21y-8=0\], which is parallel to 9x+7y+4 = 0.You need to login to perform this action.
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