JEE Main & Advanced Mathematics Straight Line Question Bank Problems related to triangle and quadrilateral Locus

  • question_answer
    A point moves so that square of its distance from the point (3, -2) is numerically equal to its distance from the line \[5x-12y=13\]. The equation of the locus of the point is  [Roorkee 1974]

    A) \[13{{x}^{2}}+13{{y}^{2}}-83x+64y+182=0\]

    B) \[{{x}^{2}}+{{y}^{2}}-11x+16y+26=0\]

    C) \[{{x}^{2}}+{{y}^{2}}-11x+16y=0\]

    D) None of these

    Correct Answer: A

    Solution :

    \[{{(h-3)}^{2}}+{{(k+2)}^{2}}=\left| \frac{5h-12k-13}{\sqrt{25+144}} \right|\].            Replace \[(h,k)\] by \[(x,\,y)\], we get            \[13{{x}^{2}}+13{{y}^{2}}-83x+64y+182=0\], which is the required equation of the locus of the point.


You need to login to perform this action.
You will be redirected in 3 sec spinner