A) \[x+y+2=0\]
B) \[x+y=2\]
C) \[x-y=2\]
D) None of these
Correct Answer: B
Solution :
We take the coordinate axes as two perpendicular lines. Let \[P\,({{x}_{1}},{{y}_{1}})\] be the required point. From \[P\,({{x}_{1}},{{y}_{1}})\], we draw PM and PN perpendicular to OX and OY respectively. Given, \[PM+PN=2\] ......(i) But, \[PM={{y}_{1}},PN={{x}_{1}}\] Hence from (i), \[{{y}_{1}}+{{x}_{1}}=2\] Thus locus of \[({{x}_{1}},{{y}_{1}})\]is \[x+y=2\] which is a straight line.You need to login to perform this action.
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