A) 10
B) \[12\frac{1}{2}\]
C) 11.1
D) 12
Correct Answer: A
Solution :
[a] Let, the cost price of article be Rs. x and given discount is m%. Then Marked price of article \[=x+25%\] of x \[=\frac{x\times 125}{100}=\text{Rs}\text{.}\,\,125x\] Now, according to the question, \[(100-m)%\] of \[125x=x+12\frac{1}{2}%\] of x \[\Rightarrow \] \[\frac{125x\times (100-x)}{100}=x+\frac{x\times 25}{2\times 100}\] \[\Rightarrow \] \[\frac{1.25x\times (100-m)}{100}=\frac{225x}{200}\] \[\Rightarrow \] \[125-1.25m=112.5\]\[\Rightarrow \]\[1.25m=12.5\] \[\therefore \] \[m=10%\] |
You need to login to perform this action.
You will be redirected in
3 sec