A) 1.5 rad
B) 1.07 rad
C) 2.07 rad
D) 0.5 rad
Correct Answer: B
Solution :
\[{{y}_{1}}={{10}^{-6}}\sin \,[100\,t+(x/50)+0.5]\] \[{{y}_{2}}={{10}^{-6}}\sin \,\left[ 100\,t+\left( \frac{x}{50} \right)+\left( \frac{\pi }{2} \right) \right]\] Phase difference f \[=[100t+(x/50)+1.57]-[100t+(x/50)+0.5]\] \[=1.07\]radians.You need to login to perform this action.
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