A) 4 cm
B) 8 cm
C) 25 cm
D) 12.5 cm
Correct Answer: C
Solution :
Comparing with \[y=a\cos (\omega t+kx-\varphi )\], We get \[k=\frac{2\pi }{\lambda }=0.02\,\Rightarrow \,\lambda =100\,cm\] Also, it is given that phase difference between particles \[\Delta \varphi =\frac{\pi }{2}.\]\[\]Hence path difference between them \[\Delta =\frac{\lambda }{2\pi }\times \Delta \varphi =\frac{\lambda }{2\pi }\times \frac{\pi }{2}=\frac{\lambda }{4}=\frac{100}{4}=25\,cm\]You need to login to perform this action.
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