A) \[{{C}_{3}}{{H}_{8}}\] and \[{{C}_{3}}{{H}_{7}}Cl\]
B) \[{{C}_{2}}{{H}_{6}}\] and \[{{C}_{2}}{{H}_{5}}Cl\]
C) \[{{C}_{2}}{{H}_{5}}Cl\] and \[{{C}_{2}}{{H}_{5}}Cl\]
D) \[{{C}_{2}}{{H}_{5}}OH\] and \[{{C}_{2}}{{H}_{5}}Cl\]
Correct Answer: D
Solution :
\[\underset{\text{(A)}}{\mathop{{{C}_{2}}{{H}_{5}}OH}}\,+PC{{l}_{5}}\to \underset{\text{(B)}}{\mathop{{{C}_{2}}{{H}_{5}}Cl}}\,+POC{{l}_{3}}+HCl\] \[\underset{\text{(B)}}{\mathop{{{C}_{2}}{{H}_{5}}Cl}}\,+KCN\to {{C}_{2}}{{H}_{5}}CN+KCl\]You need to login to perform this action.
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