A) \[C{{H}_{3}}CHFCOOH\]
B) \[FC{{H}_{2}}C{{H}_{2}}COOH\]
C) \[BrC{{H}_{2}}C{{H}_{2}}COOH\]
D) \[C{{H}_{3}}CHBrCOOH\]
Correct Answer: C
Solution :
\[BrC{{H}_{2}}C{{H}_{2}}COOH\] is least acidic or has less \[{{K}_{a}}\] i.e., dissociation constant. It is A due to lesser ?I effect of Br than F and B Br atom further away form \[-COOH\] group.
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