A) \[LiAl{{H}_{4}}\]
B) \[KMn{{O}_{4}}\]
C) \[PC{{l}_{3}}\]
D) \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}/{{H}^{+}}\]
Correct Answer: A
Solution :
\[C{{H}_{3}}COOH+4H\xrightarrow{LiAl{{H}_{4}}}C{{H}_{3}}C{{H}_{2}}-OH\]
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