A) \[C{{H}_{3}}COOH\]
B) \[C{{l}_{2}}CHCOOH\]
C) \[ClC{{H}_{2}}COOH\]
D) \[C{{l}_{3}}CCOOH\]
Correct Answer: A
Solution :
CH3COOH< ClCH2COOH< Cl2CH2COOH< Cl3CCOOH Increasing order of acidic nature.
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